To determine the maximum height reached by the tennis ball, we can use the equations of motion under constant acceleration.
Given: Initial velocity (u) = 11.3 m/s Acceleration due to gravity (g) = 9.8 m/s² (assuming no air resistance)
The ball is thrown straight up, which means the final velocity (v) when it reaches its maximum height will be zero. We can use the following equation to find the maximum height (h):
v² = u² + 2gh
Since v = 0 at the maximum height, the equation becomes:
0² = u² + 2gh
Rearranging the equation, we can solve for h:
h = (0 - u²) / (2g)
Plugging in the given values:
h = (0 - 11.3²) / (2 * 9.8) = (-127.69) / 19.6 ≈ -6.52 m
The negative sign indicates that the height is measured below the initial position of the tennis ball. However, this result doesn't make physical sense because the ball cannot travel below the point it was thrown from.
Assuming that you meant to ask for the maximum height above the point of release, we consider the magnitude of the height. Therefore, the maximum height reached by the tennis ball is approximately 6.52 meters above its starting point.