To find the maximum kinetic energy of the oscillating pendulum bob, we can use the equation for kinetic energy in simple harmonic motion (SHM), which relates it to the amplitude and angular speed of the motion.
The equation for kinetic energy in SHM is given by:
K.E. = (1/2) * m * ω^2 * A^2
Where: K.E. is the kinetic energy m is the mass of the pendulum bob (2 kg in this case) ω is the angular speed (3.0 rad/s in this case) A is the amplitude (5 cm = 0.05 m in this case)
Substituting the given values into the equation, we have:
K.E. = (1/2) * 2 kg * (3.0 rad/s)^2 * (0.05 m)^2
K.E. = (1/2) * 2 kg * 9.0 rad^2/s^2 * 0.0025 m^2
K.E. = 9.0 * 0.0025 J
K.E. = 0.0225 J
Therefore, the maximum kinetic energy of the oscillating pendulum bob is 0.0225 Joules.