To determine the number of carbon (C) atoms in 36 grams of glucose (C6H12O6), we need to use the molar mass and Avogadro's number.
Calculate the molar mass of glucose (C6H12O6): C: 6 atoms x atomic mass of carbon (12.01 g/mol) = 72.06 g/mol H: 12 atoms x atomic mass of hydrogen (1.01 g/mol) = 12.12 g/mol O: 6 atoms x atomic mass of oxygen (16.00 g/mol) = 96.00 g/mol
Total molar mass of glucose = 72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol
Determine the number of moles of glucose: Number of moles = Mass (in grams) / Molar mass Number of moles = 36 g / 180.18 g/mol ≈ 0.1999 mol (approximately)
Apply Avogadro's number to find the number of C atoms: Avogadro's number (6.022 x 10^23 atoms/mol) tells us that one mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, etc.).
Number of C atoms = Number of moles x Avogadro's number Number of C atoms = 0.1999 mol x 6.022 x 10^23 atoms/mol ≈ 1.202 x 10^23 C atoms
Therefore, there are approximately 1.202 x 10^23 carbon (C) atoms in 36 grams of glucose.