To determine the number of atoms present in a given mass of silver (Ag), we need to use the concept of Avogadro's number and the molar mass of silver.
The molar mass of silver is 107.87 g/mol, which means that one mole of silver contains 107.87 grams of silver.
To calculate the number of moles of silver in 33.89 g, we divide the given mass by the molar mass:
Number of moles of silver = 33.89 g / 107.87 g/mol ≈ 0.314 moles
Now, we can use Avogadro's number, which states that there are approximately 6.022 × 10^23 particles (atoms, molecules, or formula units) in one mole of any substance.
Number of atoms of silver = Number of moles of silver × Avogadro's number Number of atoms of silver = 0.314 moles × 6.022 × 10^23 atoms/mol
Calculating the number of atoms:
Number of atoms of silver ≈ 1.888 × 10^23 atoms
Therefore, there are approximately 1.888 × 10^23 atoms present in 33.89 g of silver.