To determine the number of oxygen atoms in 0.5 mol of anhydrous sodium sulfate (Na2SO4), we need to consider the molecular formula of sodium sulfate and the number of oxygen atoms it contains.
The molecular formula of anhydrous sodium sulfate is Na2SO4, which indicates that there are two sodium atoms (Na), one sulfur atom (S), and four oxygen atoms (O) in each molecule.
From the formula, we can determine the molar ratio between oxygen atoms and the compound. In this case, for every one molecule of Na2SO4, there are four oxygen atoms.
To calculate the number of oxygen atoms in 0.5 mol of Na2SO4, we multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) and then multiply that by the number of oxygen atoms per molecule.
Number of oxygen atoms = 0.5 mol × (6.022 x 10^23 atoms/mol) × 4 = 1.206 x 10^24 oxygen atoms
Therefore, there are approximately 1.206 x 10^24 oxygen atoms in 0.5 mol of anhydrous sodium sulfate.