To determine the number of atoms of nitrogen in 10 grams of NH4NO3 (ammonium nitrate), we need to consider the molar mass and the atomic composition of the compound.
The molar mass of NH4NO3 can be calculated by summing up the atomic masses of its constituent elements:
Molar mass of N = 14.01 g/mol Molar mass of H = 1.01 g/mol Molar mass of O = 16.00 g/mol
NH4NO3 consists of one nitrogen (N) atom, four hydrogen (H) atoms, and three oxygen (O) atoms.
Therefore, the molar mass of NH4NO3 is:
Molar mass of NH4NO3 = (1 * Molar mass of N) + (4 * Molar mass of H) + (3 * Molar mass of O) = (1 * 14.01 g/mol) + (4 * 1.01 g/mol) + (3 * 16.00 g/mol) = 80.04 g/mol
Now we can calculate the number of moles of NH4NO3 in 10 grams:
Number of moles = Mass / Molar mass = 10 g / 80.04 g/mol = 0.1249 mol (approximately)
Since there is one nitrogen (N) atom in one molecule of NH4NO3, the number of nitrogen atoms in 0.1249 moles of NH4NO3 is also 0.1249.
To convert the number of moles to the number of atoms, we need to multiply by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol.
Number of nitrogen atoms = Number of moles * Avogadro's number = 0.1249 * (6.022 x 10^23 atoms/mol) = 7.52 x 10^22 nitrogen atoms
Therefore, there are approximately 7.52 x 10^22 atoms of nitrogen in 10 grams of NH4NO3.