To determine the number of lithium (Li) atoms in 97.9 g of Li, we need to use the concept of Avogadro's number and molar mass.
The molar mass of lithium (Li) is approximately 6.94 grams/mol.
We can set up a proportion using the molar mass and Avogadro's number to find the number of Li atoms:
(97.9 g Li) / (6.94 g/mol) = (x atoms) / (6.022 x 10^23 atoms/mol)
Simplifying the proportion:
x = (97.9 g Li) × (6.022 x 10^23 atoms/mol) / (6.94 g/mol)
x ≈ 1.07 x 10^24 atoms
Therefore, there are approximately 1.07 x 10^24 lithium (Li) atoms in 97.9 g of Li.