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To determine the number of oxygen atoms present in 49 grams of H2SO4 (sulfuric acid), we need to consider the molar mass and the chemical formula of sulfuric acid.

The molar mass of sulfuric acid (H2SO4) can be calculated by adding up the atomic masses of its constituent elements:

Molar mass of H2SO4 = (2 * Atomic mass of hydrogen) + Atomic mass of sulfur + (4 * Atomic mass of oxygen)

The atomic masses of hydrogen, sulfur, and oxygen are approximately:

Atomic mass of hydrogen (H) = 1.008 g/mol Atomic mass of sulfur (S) = 32.06 g/mol Atomic mass of oxygen (O) = 16.00 g/mol

Using these values, we can calculate the molar mass of sulfuric acid:

Molar mass of H2SO4 = (2 * 1.008 g/mol) + 32.06 g/mol + (4 * 16.00 g/mol) = 2.016 g/mol + 32.06 g/mol + 64.00 g/mol = 98.076 g/mol

Now, we can calculate the number of moles of sulfuric acid in 49 grams:

Number of moles = Mass / Molar mass = 49 g / 98.076 g/mol = 0.4996 mol (approximately)

From the chemical formula of sulfuric acid (H2SO4), we can see that each molecule of sulfuric acid contains one sulfur atom (S), four oxygen atoms (O), and two hydrogen atoms (H).

Therefore, the number of oxygen atoms can be calculated by multiplying the number of moles by the number of oxygen atoms per molecule:

Number of oxygen atoms = Number of moles * Number of oxygen atoms per molecule = 0.4996 mol * 4 = 1.9984 (approximately)

So, there are approximately 1.9984 oxygen atoms present in 49 grams of H2SO4.

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