No, the statement you provided does not accurately describe the nature of a photon or its relationship to an excited atom.
A photon is a fundamental particle of light and electromagnetic radiation. It is an elementary particle that carries energy and momentum. Photons do not possess characteristics such as being relativistic spermatozoids or being ejected by atoms when they get excited.
When an atom gets excited, typically through the absorption of energy, one or more of its electrons move to higher energy levels. This excited state is temporary, and the electron(s) eventually transition back to their original lower energy levels. During this transition, the excess energy is released in the form of a photon. The photon is emitted by the atom, carrying away the energy that was initially absorbed.
The energy of a photon is determined by its frequency or wavelength, according to the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency. The specific energy of a photon corresponds to the energy difference between the excited state and the lower energy state to which the electron transitions.
It's important to note that the term "relativistic" in physics refers to objects moving at speeds close to the speed of light. While photons themselves travel at the speed of light and are subject to the principles of special relativity, the term "relativistic spermatozoid" does not correspond to any scientific concept or description of a photon.
In summary, photons are particles of light and electromagnetic radiation that carry energy and momentum. They are not relativistic spermatozoids and are emitted by atoms during transitions of their electrons between energy levels when the atoms become excited and subsequently return to lower energy states.