To determine how many moles of ammonia (NH3) will react with 49.6 moles of O2, we need to look at the balanced chemical equation for the reaction between ammonia and oxygen.
The balanced equation for the reaction is:
4 NH3 + 5 O2 -> 4 NO + 6 H2O
From the balanced equation, we can see that the stoichiometric ratio between NH3 and O2 is 4:5. This means that for every 4 moles of NH3, 5 moles of O2 are required.
To find out how many moles of NH3 will react with 49.6 moles of O2, we can set up a proportion:
4 moles NH3 / 5 moles O2 = x moles NH3 / 49.6 moles O2
Cross-multiplying and solving for x:
(4 moles NH3) * (49.6 moles O2) = (5 moles O2) * (x moles NH3)
198.4 moles NH3 = 5x
Dividing both sides by 5:
x = 198.4 moles NH3 / 5
x ≈ 39.68 moles NH3
Therefore, approximately 39.68 moles of ammonia (NH3) will react with 49.6 moles of O2.