The chemical formula Cu2(SO4)3 suggests the presence of two copper ions (Cu2+) and three sulfate ions (SO4^2-).
To determine the oxidation state of copper (Cu) in Cu2(SO4)3, we can use the fact that the overall charge of the compound must be zero.
Each sulfate ion (SO4^2-) has a charge of -2. Since there are three sulfate ions in the formula, the total charge contributed by sulfate ions is (3 × -2) = -6.
Thus, the oxidation state of copper (Cu) can be calculated as follows:
2Cu + (-6) = 0
2Cu = +6
Cu = +3
Therefore, the oxidation state of copper (Cu) in Cu2(SO4)3 is +3.