To determine the number of moles of calcium bicarbonate (Ca(HCO3)2) in 1296 g, we need to divide the given mass by the molar mass of calcium bicarbonate.
The molar mass of calcium bicarbonate can be calculated by summing the atomic masses of its constituent elements. Here's the calculation:
Calcium (Ca) has an atomic mass of approximately 40.08 g/mol. Hydrogen (H) has an atomic mass of approximately 1.01 g/mol. Carbon (C) has an atomic mass of approximately 12.01 g/mol. Oxygen (O) has an atomic mass of approximately 16.00 g/mol.
Molar mass of calcium bicarbonate (Ca(HCO3)2): = (1 × Ca) + (2 × H) + (1 × C) + (6 × O) = (1 × 40.08 g/mol) + (2 × 1.01 g/mol) + (1 × 12.01 g/mol) + (6 × 16.00 g/mol) = 40.08 g/mol + 2.02 g/mol + 12.01 g/mol + 96.00 g/mol = 150.11 g/mol
Now, we can calculate the number of moles using the given mass and molar mass:
Number of moles = Mass / Molar mass = 1296 g / 150.11 g/mol ≈ 8.635 moles
Therefore, there are approximately 8.635 moles of calcium bicarbonate in 1296 g of calcium bicarbonate.