To determine the volume of 11 M H2SO4 needed to achieve a concentration of 0.105 M in 8.6 liters of water, we can use the formula for dilution:
C1V1 = C2V2
Where: C1 = initial concentration V1 = initial volume C2 = final concentration V2 = final volume
Given: C1 = 11 M (concentration of the stock solution) V1 = volume of the stock solution (to be determined) C2 = 0.105 M (final desired concentration) V2 = 8.6 liters (final volume)
Let's substitute the values into the formula and solve for V1:
11 M * V1 = 0.105 M * 8.6 L
V1 = (0.105 M * 8.6 L) / 11 M
V1 ≈ 0.081 L or 81 mL
Therefore, approximately 81 mL of 11 M H2SO4 needs to be dissolved in 8.6 liters of water to obtain a concentration of 0.105 M.