To find the molar concentration of NaOH(aq) in the given titration, you can use the concept of stoichiometry and the balanced chemical equation for the reaction between NaOH and HCl:
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
Based on the balanced equation, we can see that the ratio between NaOH and HCl is 1:1. This means that one mole of NaOH reacts with one mole of HCl.
Given: Volume of NaOH(aq) = 12.0 mL = 0.0120 L Molar concentration of HCl(aq) = 0.15 M Volume of HCl(aq) = 16.0 mL = 0.0160 L
Using the equation C₁V₁ = C₂V₂, where C₁ and V₁ are the concentration and volume of the first solution, and C₂ and V₂ are the concentration and volume of the second solution, we can calculate the molar concentration of NaOH(aq):
C₁V₁ = C₂V₂ C₁ * 0.0120 L = 0.15 M * 0.0160 L
Solving for C₁: C₁ = (0.15 M * 0.0160 L) / 0.0120 L C₁ ≈ 0.20 M
Therefore, the molar concentration of NaOH(aq) is approximately 0.20 M.