Question

A solution is prepared by dissolving 10.0g sucrose in 50g water. The volume of the resulting solution is 52 ml. What is the molarity?

Answer 1

To find the molarity of a solution, you need to calculate the number of moles of solute (sucrose) and then divide it by the volume of the solution in liters. Here's how you can do that:

1. Calculate the number of moles of sucrose: Molar mass of sucrose (C12H22O11) = (12.01 g/mol × 12) + (1.01 g/mol × 22) + (16.00 g/mol × 11) = 342.3 g/mol

Mass of sucrose = 10.0 g

Number of moles of sucrose = Mass of sucrose / Molar mass of sucrose = 10.0 g / 342.3 g/mol = 0.0292 mol (rounded to four decimal places)

2. Convert the volume of the solution to liters: Volume of the solution = 52 mL = 52/1000 L = 0.052 L

3. Calculate the molarity: Molarity (M) = Number of moles of solute / Volume of solution in liters = 0.0292 mol / 0.052 L ≈ 0.562 M (rounded to three decimal places)

Therefore, the molarity of the solution is approximately 0.562 M.