To determine the mass of zinc (Zn) required to react with 0.25 moles of hydrochloric acid (HCl), we need to use the stoichiometry of the balanced chemical equation:
Zn + 2HCl -> ZnCl2 + H2
From the equation, we can see that the mole ratio between zinc and hydrochloric acid is 1:2. Therefore, for every 1 mole of zinc, 2 moles of hydrochloric acid react.
Given that we have 0.25 moles of hydrochloric acid, we can set up a proportion to calculate the moles of zinc required:
(1 mole Zn / 2 moles HCl) = (x moles Zn / 0.25 moles HCl)
Solving for x, we find:
x = (1 mole Zn / 2 moles HCl) * 0.25 moles HCl x = 0.125 moles Zn
Now, we can calculate the mass of zinc using its molar mass:
Molar mass of Zn = 65.38 g/mol
Mass of Zn = Moles of Zn * Molar mass of Zn = 0.125 moles Zn * 65.38 g/mol = 8.1735 g Zn
Therefore, approximately 8.1735 grams of zinc are required to react with 0.25 moles of hydrochloric acid.