To determine the number of grams of N₂ needed to produce 24.83 mol of NH₃, we can use the balanced chemical equation for the reaction between N₂ and H₂ to form NH₃:
N₂ + 3H₂ → 2NH₃
From the equation, we can see that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃. This means that the stoichiometric ratio between N₂ and NH₃ is 1:2.
To calculate the grams of N₂ needed, we need to use the molar mass of N₂, which is approximately 28.02 g/mol.
First, let's calculate the number of moles of N₂ required: Moles of N₂ = (Moles of NH₃) / (Stoichiometric coefficient of NH₃) = 24.83 mol / 2 = 12.415 mol
Next, we can convert moles of N₂ to grams using the molar mass of N₂: Grams of N₂ = (Moles of N₂) x (Molar mass of N₂) = 12.415 mol x 28.02 g/mol ≈ 347.13 g
Therefore, to produce 24.83 mol of NH₃, you would need approximately 347.13 grams of N₂.