+17 votes
in Chemistry by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+11 votes
by

To determine the amount of hydrogen gas produced in the reaction between zinc (Zn) and hydrochloric acid (HCl), we need to balance the equation and use stoichiometry.

The balanced equation for the reaction is:

Zn + 2HCl → ZnCl2 + H2

From the balanced equation, we can see that one mole of zinc reacts with two moles of HCl to produce one mole of hydrogen gas.

First, we need to convert the masses of zinc and HCl into moles using their respective molar masses.

Molar mass of zinc (Zn) = 65.38 g/mol Molar mass of HCl = 36.46 g/mol

Number of moles of zinc (Zn) = mass of zinc / molar mass of zinc = 6.5 g / 65.38 g/mol ≈ 0.0994 mol

Number of moles of HCl = mass of HCl / molar mass of HCl = 5.0 g / 36.46 g/mol ≈ 0.137 mol

According to the stoichiometry of the balanced equation, 1 mole of zinc reacts with 2 moles of HCl to produce 1 mole of hydrogen gas. Therefore, the number of moles of hydrogen gas produced is equal to half the number of moles of HCl used.

Number of moles of hydrogen gas = 0.137 mol / 2 = 0.0685 mol

Finally, we can convert the moles of hydrogen gas into grams using the molar mass of hydrogen (H2).

Molar mass of hydrogen (H2) = 2.02 g/mol

Mass of hydrogen gas = number of moles of hydrogen gas * molar mass of hydrogen = 0.0685 mol * 2.02 g/mol ≈ 0.1387 g

Therefore, approximately 0.1387 grams of hydrogen gas would be produced in the reaction between 6.5 grams of zinc and 5.0 grams of HCl.

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...