To find the value of m3+m−3m^3 + m^{ -3}m3+m−3, we can use a clever algebraic manipulation. Let's start by squaring the equation m2+m−2=23m^2 + m^{ -2} = 23m2+m−2=23:
(m2+m−2)2=232(m^2 + m^{ -2})^2 = 23^2(m2+m−2)2=232
Expanding the left side of the equation using the binomial theorem:
m4+2m2⋅m−2+(m−2)2=529m^4 + 2m^2 cdot m^{ -2} + (m^{ -2})^2 = 529m4+2m2⋅m−2+(m−2)2=529
Simplifying:
m4+2+m−4=529m^4 + 2 + m^{ -4} = 529m4+2+m<span class="msupsub