To determine the volume of hydrochloric acid (HCl) needed to neutralize sodium carbonate (Na2CO3), we need to consider the balanced chemical equation for the reaction between the two compounds:
2 HCl + Na2CO3 -> 2 NaCl + H2O + CO2
From the equation, we can see that it takes two moles of hydrochloric acid to react with one mole of sodium carbonate. Therefore, the stoichiometric ratio is 2:1 for HCl to Na2CO3.
To calculate the volume of HCl needed, we require additional information such as the concentration (molarity) of the HCl solution and the amount (in moles or mass) of sodium carbonate.
If you provide the concentration of the HCl solution and the amount of sodium carbonate, I can assist you with the calculation.