To find the moles of nitrogen gas (N2) produced in the reaction 2NaN3(s) → 2Na(s) + 3N2(g), you can use stoichiometry. The balanced equation tells you the mole ratio between NaN3 and N2.
According to the equation, 2 moles of NaN3 produce 3 moles of N2. Therefore, the mole ratio is 2:3.
If you know the number of moles of NaN3, you can use this ratio to calculate the moles of N2 produced. Let's say you have x moles of NaN3.
Moles of NaN3: x moles Moles of N2: (3/2) * x moles
So, to find the moles of N2, you multiply the moles of NaN3 by the mole ratio (3/2).
For example, if you have 4 moles of NaN3: Moles of N2 = (3/2) * 4 moles = 6 moles of N2.
Make sure to use the appropriate mole ratio from the balanced equation when applying stoichiometry to calculate the moles of a specific substance in a reaction.