To determine the number of pounds of nitrogen in 700 lb of calcium nitrite, we need to consider the molecular formula of calcium nitrite (Ca(NO₂)₂) and calculate the molar mass of nitrogen.
The molar mass of nitrogen (N) is approximately 14.01 grams per mole (g/mol).
Next, we calculate the molar mass of calcium nitrite (Ca(NO₂)₂) as follows:
- Molar mass of calcium (Ca) = 40.08 g/mol
- Molar mass of nitrite (NO₂) = (14.01 g/mol for nitrogen + 16.00 g/mol for oxygen) × 2 = 62.02 g/mol
The molar mass of calcium nitrite (Ca(NO₂)₂) is: 40.08 g/mol (calcium) + 62.02 g/mol (nitrite) × 2 = 164.12 g/mol
Now, we can calculate the number of moles of calcium nitrite in 700 lb by converting pounds to grams and then to moles: 700 lb × 453.592 g/lb = 317,514.4 g 317,514.4 g / 164.12 g/mol = 1,935.29 mol
Finally, we calculate the number of pounds of nitrogen by multiplying the number of moles of calcium nitrite by the molar mass of nitrogen: 1,935.29 mol × 14.01 g/mol = 27,102.29 g
Converting grams to pounds: 27,102.29 g / 453.592 g/lb ≈ 59.78 lb
Therefore, there are approximately 59.78 pounds of nitrogen in 700 pounds of calcium nitrite.