To determine the temperature at which the volume of a gas will be 3 liters, assuming the pressure remains constant, we can use the combined gas law equation. The combined gas law states:
(P₁V₁) / T₁ = (P₂V₂) / T₂
where: P₁ and P₂ are the initial and final pressures (constant in this case), V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature (27⁰C in this case), and T₂ is the final temperature (to be determined).
Let's plug in the values we know:
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Since the pressure remains constant, P₁ / T₁ = P₂ / T₂. We can rewrite the equation as:
V₁ / T₁ = V₂ / T₂
Now, we can solve for T₂:
T₂ = (V₂ * T₁) / V₁
Plugging in the values:
T₂ = (3 * 27⁰C) / 2
Calculating the value:
T₂ = 81⁰C / 2
T₂ = 40.5⁰C
Therefore, the temperature at which the volume of the gas will be 3 liters, with constant pressure, is approximately 40.5⁰C.