To calculate the amount of carbon dioxide (CO2) produced by burning 30 grams of calcium carbonate (CaCO3), we need to consider the chemical equation for the combustion of calcium carbonate:
CaCO3(s) → CaO(s) + CO2(g)
From the equation, we can see that one mole of calcium carbonate produces one mole of carbon dioxide. The molar mass of calcium carbonate is:
CaCO3: 40.08 g/mol (calcium) + 12.01 g/mol (carbon) + (3 * 16.00 g/mol) (oxygen) = 40.08 g/mol + 12.01 g/mol + 48.00 g/mol = 100.09 g/mol
To calculate the number of moles of calcium carbonate in 30 grams, we divide the mass by the molar mass:
Number of moles = mass / molar mass = 30 g / 100.09 g/mol = 0.2998 mol (approximately)
Since the stoichiometry of the reaction tells us that one mole of calcium carbonate produces one mole of carbon dioxide, the number of moles of carbon dioxide produced is also 0.2998 mol.
To convert the moles of carbon dioxide to grams, we need to multiply by the molar mass of carbon dioxide:
Molar mass of CO2: 12.01 g/mol (carbon) + (2 * 16.00 g/mol) (oxygen) = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol
Mass of carbon dioxide = moles of CO2 * molar mass of CO2 = 0.2998 mol * 44.01 g/mol = 13.192 g
Therefore, burning 30 grams of calcium carbonate produces approximately 13.192 grams of carbon dioxide.