To calculate the molarity of a solution, we need to determine the number of moles of solute (sucrose, C12H22O11) and divide it by the volume of the solution in liters.
Given: Mass of sucrose (C12H22O11) = 0.575 g Volume of solution = 2.5 L
Step 1: Calculate the number of moles of sucrose. To find the moles of sucrose, we divide the given mass by its molar mass. The molar mass of sucrose (C12H22O11) can be calculated by summing the atomic masses of its constituent elements.
Molar mass of carbon (C) = 12.01 g/mol Molar mass of hydrogen (H) = 1.01 g/mol Molar mass of oxygen (O) = 16.00 g/mol
Molar mass of sucrose (C12H22O11): = (12 * 12.01 g/mol) + (22 * 1.01 g/mol) + (11 * 16.00 g/mol) = 144.12 g/mol + 22.22 g/mol + 176.00 g/mol = 342.34 g/mol
Now, we can calculate the number of moles of sucrose: Moles = Mass / Molar mass Moles = 0.575 g / 342.34 g/mol
Step 2: Calculate the molarity of the solution. Molarity (M) = Moles / Volume
Molarity = (0.575 g / 342.34 g/mol) / 2.5 L
Performing the calculation: Molarity ≈ 0.001062 M (rounded to 6 decimal places)
Therefore, the molarity of the solution is approximately 0.001062 M.