Question

A car is running in the velocity of 20 m/s. After 30 s, it covers a distance of 1200 m. What will be its final velocity and acceleration?

Answer 1

To find the final velocity and acceleration of the car, we can use the equations of motion. The equations we'll need are:

1. Displacement (s) = Initial velocity (u) * time (t) + (1/2) * acceleration (a) * time^2
2. Final velocity (v) = Initial velocity (u) + acceleration (a) * time (t)

Given information: Initial velocity (u) = 20 m/s Time (t) = 30 s Displacement (s) = 1200 m

We'll start by rearranging equation 1 to solve for acceleration (a): s = ut + (1/2)at^2 1200 = 20 * 30 + (1/2) * a * (30^2) 1200 = 600 + 15a * 900 1200 - 600 = 13500a 600 = 13500a a = 600 / 13500 a ≈ 0.0444 m/s^2

Now, we can substitute the values of initial velocity (u), time (t), and acceleration (a) into equation 2 to find the final velocity (v): v = u + at v = 20 + 0.0444 * 30 v = 20 + 1.332 v ≈ 21.332 m/s

Therefore, the final velocity of the car is approximately 21.332 m/s, and the acceleration is approximately 0.0444 m/s^2.