Question

A tract covers 40m in 8.5s while smoothly slowing down to a final speed of 2.8m/s. What is its original velocity and its acceleration?

Answer 1

To determine the original velocity and acceleration of the tractor, we can use the equation of motion that relates distance, initial velocity, final velocity, acceleration, and time. The equation is:

$\text{Distance}=\text{Initial velocity}\times \text{Time}+\frac{1}{2}\times \text{Acceleration}\times {\text{Time}}^2$

Given that the tractor covers a distance of 40m in 8.5s and slows down to a final speed of 2.8m/s, we can use this information to solve for the original velocity and acceleration.

Step 1: Determine the final velocity: Final velocity (v) = 2.8 m/s

Step 2: Calculate the time taken to slow down: Time (t) = 8.5 s

Step 3: Calculate the distance covered: Distance (d) = 40 m

Step 4: Rearrange the equation of motion to solve for the initial velocity: $d=v_{\text{initial}}\times t+\frac{1}{2}\times a\times t^2$

40=vinitial×8.5+12×a×(8.5)240 = v_{ ext{initial}} imes 8.5 + frac{1}{2} imes a imes (8.5)^240=vinitial​×8.5+21​×a×(8.5)<