To determine the initial velocity of the object when it was thrown and its velocity when it reached the ground, we can use kinematic equations and consider the motion of the object under the influence of gravity.
Let's assume the initial velocity of the object when it was thrown is u (m/s), the final velocity when it reaches the ground is v (m/s), the time of flight is t (seconds), and the height from which it was thrown is h (meters).
Given: h = 50 meters t = 10 seconds
- The equation for the vertical displacement (h) of an object in free fall is: h = ut + (1/2)gt^2 Here, g represents the acceleration due to gravity, which is approximately 9.8 m/s^2 near the surface of the Earth.
Plugging in the values: 50 = u * 10 + (1/2) * 9.8 * (10)^2
- The equation for the final velocity (v) of an object in free fall is: v = u + gt
Plugging in the values: v = u + 9.8 * 10
Now, we can solve these two equations simultaneously to find the initial velocity (u) and the final velocity (v).
From equation 1: 50 = 10u + 0.5 * 9.8 * 100 50 = 10u + 490
Rearranging the equation: 10u = 50 - 490 10u = -440 u = -44 m/s
From equation 2: v = u + 9.8 * 10 v = -44 + 98 v = 54 m/s
Therefore, the object was thrown with an initial velocity of -44 m/s (negative sign indicates upward direction) and its velocity when it reached the ground was 54 m/s (positive sign indicates downward direction).