Question

Starting at the origin, an object has a velocity of 2 m/s and an acceleration of 1 m/S2. What is its final position after 2 seconds?

Answer 1

To find the object's final position after 2 seconds, we can use the kinematic equation:

$x=x_0+v_{0}t+\frac{1}{2}a{t}^2$

Where:

• $x$ is the final position
• $x_0$ is the initial position (in this case, the origin, so $x_0=0$)
• $v_0$ is the initial velocity
• $t$ is the time
• $a$ is the acceleration

Given:

• $v_0=2$ m/s (initial velocity)
• $a=1$ m/s² (acceleration)
• $t=2$ s (time)

Plugging in these values into the equation, we have:

x=0+2⋅2+12⋅1⋅(22