To determine the height from which the ball was thrown, we can use the kinematic equation for vertical motion:
h = ut + (1/2)gt^2
where: h is the height u is the initial vertical velocity (upward) t is the time g is the acceleration due to gravity
Given: u = 0.8 m/s (upward) t = 0.6 s g = 9.8 m/s² (acceleration due to gravity)
Plugging in the values into the equation, we get:
h = (0.8 m/s)(0.6 s) + (1/2)(9.8 m/s²)(0.6 s)^2
h = 0.48 m + (1/2)(9.8 m/s²)(0.36 s²)
h = 0.48 m + (0.5)(9.8 m/s²)(0.1296 s²)
h = 0.48 m + 0.6336 m
h ≈ 1.1136 m
Therefore, the ball was thrown from a height of approximately 1.1136 meters.