To find the acceleration of an object when an additional force is applied, we can use Newton's second law of motion, which states that the force acting on an object is equal to the product of its mass and acceleration:
F=m⋅aF = m cdot aF=m⋅a
where:
- FFF is the force applied to the object,
- mmm is the mass of the object, and
- aaa is the acceleration.
In this case, we are given:
- m=10 kgm = 10 , ext{kg}m=10kg (mass of the object),
- v=5 m/sv = 5 , ext{m/s}v=5m/s (velocity of the object), and
- F=20 NF = 20 , ext{N}F=20N (additional force applied to the object).
However, we need to convert the force from joules (J) to newtons (N). Force is measured in newtons, not joules. So, we have: F=20 JF = 20 , ext{J}F=20J
To calculate the acceleration, we rearrange the formula:
a=Fma = frac{F}{m}a=mF
Plugging in the values, we have: a=20 N10 kg=2 m/s2a = frac{20 , ext{N}}{10 , ext{kg}} = 2 , ext{m/s}^2a=10kg20N=2m/s2
Therefore, the acceleration of the object is 2 m/s22 , ext{m/s}^22<span cla