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To solve this problem, let's first convert the time from minutes to seconds:

10 minutes = 10 × 60 seconds = 600 seconds

Given: Mass of the tractor (m) = 1500 kg Initial velocity (u) = 0 m/s (since it starts from rest) Final velocity (v) = 20 m/s Time taken (t) = 600 seconds

We can use the equation of motion:

v = u + at

Where: v = final velocity u = initial velocity a = acceleration t = time taken

Substituting the known values:

20 m/s = 0 m/s + a × 600 s

Simplifying the equation:

20 m/s = 600 a

Now, we can solve for the acceleration (a):

a = 20 m/s / 600 s a ≈ 0.0333 m/s²

So, the acceleration of the tractor is approximately 0.0333 m/s².

To find the distance covered (s), we can use another equation of motion:

s = ut + (1/2)at²

Where: s = distance covered

Substituting the values:

s = 0 m/s × 600 s + (1/2) × 0.0333 m/s² × (600 s)²

Simplifying the equation:

s = 0 + 0.5 × 0.0333 m/s² × 360,000 s²

s ≈ 6,000 m

So, the distance covered by the tractor is approximately 6,000 meters.

To calculate the net force (F) acting on the tractor, we can use Newton's second law of motion:

F = ma

Where: m = mass of the tractor a = acceleration

Substituting the values:

F = 1500 kg × 0.0333 m/s²

F ≈ 49.95 N

So, the net force acting on the tractor as it accelerates is approximately 49.95 Newtons.

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