+58 votes
in Classical Mechanics by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+33 votes
by

When a body is projected horizontally, its initial vertical velocity is zero. The only force acting on the body is gravity, causing it to accelerate vertically downward.

The time taken for an object to fall freely from a height can be calculated using the equation:

h = (1/2) * g * t^2

where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.

In this case, the initial vertical velocity is zero, and the height h is 5 m. Rearranging the equation, we get:

t = sqrt((2 * h) / g)

t = sqrt((2 * 5) / 9.8) t ≈ 1.02 s (rounded to two decimal places)

Since the body is projected horizontally, its horizontal velocity remains constant throughout its motion. Therefore, the horizontal velocity at the point of impact (reaching the ground) is also 23 m/s.

In summary, the velocity of the body on reaching the ground is 23 m/s horizontally and 0 m/s vertically.

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...