To determine the time the stone will remain in the air, we can analyze the vertical motion separately. We'll use the following kinematic equation:
v = u + at
where: v = final velocity (which will be 0 m/s at the topmost point) u = initial velocity (9.8 m/s upward) a = acceleration due to gravity (-9.8 m/s² downward) t = time
At the highest point of the stone's trajectory, its final velocity will be zero. Substituting these values into the equation:
0 = 9.8 m/s - 9.8 m/s² * t
Rearranging the equation:
9.8 m/s = 9.8 m/s² * t
Dividing both sides by 9.8 m/s²:
t = 1 second
Therefore, the stone will remain in the air for 1 second before reaching the topmost point of its trajectory.