For the acceleration of a particle moving along a straight line is a=-0.2v2m/s2 where vis in m/s. If the initial velocity v=80M/s at t=0, what is the velocity when t=2 seconds?

Question

For the acceleration of a particle moving along a straight line is a=-0.2v2m/s2 where vis in m/s. If the initial velocity v=80M/s at t=0, what is the velocity when t=2 seconds?

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LuminousSculptor · Answer 1 · 2023-03-14T10:03:25+0000

To solve this problem, we can use the equation of motion:

v = u + at,

where: v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Given: Initial velocity, u = 80 m/s, Acceleration, a = -0.2 v^2 m/s^2, Time, t = 2 s.

First, we need to find the value of acceleration using the given expression:

a = -0.2 v^2

Substituting the initial velocity u = 80 m/s:

-0.2 (80)^2 = -0.2 * 6400 = -1280 m/s^2.

Now, we can use the equation of motion to find the final velocity:

v = u + at.

Substituting the known values:

v = 80 + (-1280) * 2 = 80 - 2560 = -2480 m/s.

Therefore, when t = 2 seconds, the velocity of the particle is -2480 m/s. Please note that the negative sign indicates that the velocity is in the opposite direction of the initial velocity.

For the acceleration of a particle moving along a straight line is a=-0.2v2m/s2 where vis in m/s. If the initial velocity v=80M/s at t=0, what is the velocity when t=2 seconds?

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For the acceleration of a particle moving along a straight line is a=-0.2v*2m/s*2 where vis in m/s. If the initial velocity v=80M/s at t=0, what is the velocity when t=2 seconds?

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Your comment on this answer:

For the acceleration of a particle moving along a straight line is a=-0.2v2m/s2 where vis in m/s. If the initial velocity v=80M/s at t=0, what is the velocity when t=2 seconds?