To calculate the work done by the child while pulling the wagon, we can use the formula:
Work=Force×Distance×cos(θ) ext{Work} = ext{Force} imes ext{Distance} imes cos( heta)Work=Force×Distance×cos(θ)
where:
- Force is the magnitude of the force applied (22 N),
- Distance is the distance over which the force is applied (4.3 m),
- θ is the angle between the direction of the force and the direction of motion (assuming it's 0° since the child is pulling in the same direction as the motion).
Substituting the values into the formula:
Work=22 N×4.3 m×cos(0°) ext{Work} = 22 , ext{N} imes 4.3 , ext{m} imes cos(0°)Work=22N×4.3m×cos(0°)
Since the cosine of 0° is 1, the equation simplifies to:
Work=22 N×4.3 m×1 ext{Work} = 22 , ext{N} imes 4.3 , ext{m} imes 1Work=22N×4.3m×1
Work=94.6 J ext{Work} = 94.6 , ext{J}Work=94.6J
Therefore, the child would do 94.6 joules of work while pulling the 12-kg wagon a distance of 4.3 m with a 22 N force.