Question

How far would an object go in 2.5 seconds if it started at rest with constant acceleration 30 m/s^2 moving along a straight line?

Answer 1

To calculate the distance covered by an object with constant acceleration, you can use the kinematic equation:

$s=ut+\frac{1}{2}a{t}^2$

Where:

• $s$ is the distance traveled
• $u$ is the initial velocity (in this case, 0 m/s since the object started at rest)
• $a$ is the acceleration (30 m/s${}^2$)
• $t$ is the time taken (2.5 seconds)

Plugging in the values, we have:

$s=0\cdot 2.5+\frac{1}{2}\cdot 30\cdot (2.5{)}^2$

Simplifying further:

$s=0+0.5\cdot 30\cdot 6.25$

$s=0+93.75$

Therefore, the object would travel a distance of 93.75 meters in 2.5 seconds with a constant acceleration of 30 m/s2^2<span class="vli