Question

A car starts from rest and moves with uniform acceleration of 2m/s2. How much time will taken to cover a distance of 49m?

Answer 1

To determine the time it takes for the car to cover a distance of 49 meters with a uniform acceleration of 2 m/s², we can use the following kinematic equation:

$s=ut+\frac{1}{2}a{t}^2$

Where:

• $s$ is the distance traveled (49 meters)
• $u$ is the initial velocity (0 m/s since the car starts from rest)
• $a$ is the acceleration (2 m/s²)
• $t$ is the time taken (unknown)

Rearranging the equation to solve for $t$:

$t^2+2u\cdot t-\frac{2s}{a}=0$

Plugging in the values, we have:

$t^2+2\cdot 0\cdot t-\frac{2\cdot 49}{2}=0$

t2−49=0t^2 - 49 = 0<span class="strut" style="height: 0.8974