To determine the minimum force required to start the box sliding, we need to consider the static friction acting between the box and the wooden floor. The maximum static friction force can be calculated using the equation:
F_static_max = μ_static * N
where: F_static_max is the maximum static friction force, μ_static is the coefficient of static friction, and N is the normal force exerted on the box.
The normal force N is equal to the weight of the box, which can be calculated using the equation:
N = m * g
where: m is the mass of the box and g is the acceleration due to gravity (approximately 9.8 m/s²).
Given that the mass of the box is 2 kg, we can calculate the normal force:
N = 2 kg * 9.8 m/s² = 19.6 N
Now, we can calculate the maximum static friction force:
F_static_max = 0.6 * 19.6 N = 11.76 N
Therefore, a minimum force greater than 11.76 N is required to start the box sliding.
To determine the minimum force required to keep the box sliding, we need to consider the kinetic friction acting between the box and the wooden floor. The kinetic friction force can be calculated using the equation:
F_kinetic = μ_kinetic * N
where: F_kinetic is the kinetic friction force, μ_kinetic is the coefficient of kinetic friction, and N is the normal force.
Using the same normal force value of 19.6 N, we can calculate the kinetic friction force:
F_kinetic = 0.35 * 19.6 N = 6.86 N
Therefore, a minimum force greater than 6.86 N is required to keep the box sliding.