Question

What is the magnitude of and direction of its acceleration if a coach travels eastward at 12.6m/s after 10s its velocity is 9.5m/a?

Answer 1

To determine the magnitude and direction of the acceleration, we can use the equation:

$a=\frac{v_f-v_i}{t}$

Where:

• $a$ is the acceleration
• $v_f$ is the final velocity
• $v_i$ is the initial velocity
• $t$ is the time

Given that the coach is traveling eastward, we'll consider velocities in the positive direction as east and in the negative direction as west.

We have the following information:

• Initial velocity ($v_i$) = 12.6 m/s (east)
• Final velocity ($v_f$) = 9.5 m/s (east)
• Time ($t$) = 10 s

Substituting these values into the equation, we can calculate the acceleration:

$a=\frac{v_f-v_i}{t}$