Question

A body moving with an initial velocity of 20 m/s has an acceleration of 4 m/s^2. Find the velocity of the moving body after 4s and distance traveled in that time?

Answer 1

To find the velocity of the moving body after 4 seconds and the distance traveled in that time, we can use the equations of motion.

Given: Initial velocity (u) = 20 m/s Acceleration (a) = 4 m/s² Time (t) = 4 s

1. To find the final velocity (v), we can use the equation: v = u + at

Substituting the given values: v = 20 m/s + (4 m/s²)(4 s) v = 20 m/s + 16 m/s v = 36 m/s

Therefore, the velocity of the moving body after 4 seconds is 36 m/s.

2. To find the distance traveled (s), we can use the equation: s = ut + (1/2)at²

Substituting the given values: s = (20 m/s)(4 s) + (1/2)(4 m/s²)(4 s)² s = 80 m + 8 m/s² × 16 s² s = 80 m + 128 m s = 208 m

Therefore, the distance traveled by the body in 4 seconds is 208 meters.