Question

If an object is moving from a rest, and it's velocity reached 25m/s after 15s. What is the distance travelled during that period?

Answer 1

To find the distance traveled during the given time period, we can use the equation of motion:

$\text{Distance}=\text{Initial Velocity}\times \text{Time}+\frac{1}{2}\times \text{Acceleration}\times {\text{Time}}^2$

In this case, the object starts from rest, so the initial velocity ($v_0$) is 0 m/s. The equation simplifies to:

$\text{Distance}=\frac{1}{2}\times \text{Acceleration}\times {\text{Time}}^2$

We're given that the final velocity ($v$) is 25 m/s, and the time ($t$) is 15 s. Since the object started from rest, the average acceleration ($a$) during this period can be calculated using:

$a=\frac{v-v_0}{t}$

Substituting the given values:

a=25 m/s−0 m/s15 s</mro