To solve this problem, we need to convert the velocities to a consistent unit. Let's convert both velocities to meters per second (m/s):
Initial velocity (u) = 30 km/hr Final velocity (v) = 90 km/hr Acceleration (a) = 1 m/s²
Converting velocities: u = 30 km/hr * (1000 m/1 km) / (3600 s/1 hr) ≈ 8.33 m/s
v = 90 km/hr * (1000 m/1 km) / (3600 s/1 hr) ≈ 25 m/s
We can use the following equation to find the distance (s) traveled:
v² = u² + 2as
Plugging in the known values:
25² = 8.33² + 2 * 1 * s
625 = 69.44 + 2s
2s = 625 - 69.44 2s ≈ 555.56
s ≈ 277.78 meters
Therefore, the distance traveled from the place where acceleration began to the point where the velocity reaches 90 km/hr is approximately 277.78 meters.