Question

A ball rolling down a Hill uniformly accelerated at 4 m/s^2. assuming that it starts from rest, what is its speed at the end of each of the first 3 seconds?

Answer 1

To find the speed of the ball at the end of each of the first three seconds, we can use the equation of motion:

v = u + at

where: v = final velocity u = initial velocity (in this case, the ball starts from rest, so u = 0) a = acceleration (given as 4 m/s^2) t = time

Let's calculate the speed at the end of each second:

For t = 1 second: v = 0 + (4 m/s^2)(1 s) = 4 m/s

For t = 2 seconds: v = 0 + (4 m/s^2)(2 s) = 8 m/s

For t = 3 seconds: v = 0 + (4 m/s^2)(3 s) = 12 m/s

Therefore, the speed of the ball at the end of the first second is 4 m/s, at the end of the second second is 8 m/s, and at the end of the third second is 12 m/s.