Question

What is the final velocity of a body, starting from rest, that accelerates uniformly at a rate of 100 m/s square for ten seconds, and what was the distance traveled during this time?

Answer 1

To find the final velocity and distance traveled by a body that starts from rest and accelerates uniformly at a rate of 100 m/s² for ten seconds, we can use the following equations:

1. Final velocity (v) can be calculated using the equation: v = u + at

2. Distance traveled (s) can be calculated using the equation: s = ut + (1/2)at²

Given: Initial velocity (u) = 0 m/s (starting from rest) Acceleration (a) = 100 m/s² Time (t) = 10 s

Let's calculate the final velocity:

v = u + at v = 0 + (100 m/s²)(10 s) v = 1000 m/s

The final velocity of the body after 10 seconds of acceleration is 1000 m/s.

Now, let's calculate the distance traveled:

s = ut + (1/2)at² s = (0 m/s)(10 s) + (1/2)(100 m/s²)(10 s)² s = 0 + (1/2)(100 m/s²)(100 s²) s = (1/2)(10000 m) s = 5000 m

The distance traveled by the body during this time is 5000 meters.