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To find the initial acceleration, we need to differentiate the position function with respect to time and evaluate it at the initial time (t = 0).

Given the position function:

s = 3t + ⅔t² - 2t³

To find the velocity function, differentiate the position function with respect to time:

v = ds/dt

Taking the derivative of each term separately:

v = d/dt(3t) + d/dt(⅔t²) - d/dt(2t³) v = 3 + ⅔(2t) - 3(2t²)

Simplifying:

v = 3 + ⅔(2t) - 6t²

Now, to find the acceleration function, differentiate the velocity function with respect to time:

a = dv/dt

Taking the derivative of each term separately:

a = d/dt(3 + ⅔(2t) - 6t²) a = 0 + ⅔(2) - 6(2t)

Simplifying:

a = ⅔ - 12t

To find the initial acceleration, substitute the initial time (t = 0) into the acceleration function:

a_initial = ⅔ - 12(0) a_initial = ⅔

Therefore, the initial acceleration is ⅔.

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