Question

When the brake is applied in a vehicle travelling with a velocity of 25m/s, the retardation becomes 0.5m/S. How far will it travel in 15 seconds?

Answer 1

To determine the distance traveled by a vehicle under braking, we can use the kinematic equation:

$v^2=u^2+2as$

where:

• $v$ is the final velocity (0 m/s since the vehicle comes to a stop)
• $u$ is the initial velocity (25 m/s)
• $a$ is the acceleration (retardation, which is -0.5 m/s${}^2$ since it opposes the motion)
• $s$ is the distance traveled

Rearranging the equation, we have:

$s=\frac{v^2-u^2}{2a}$

Substituting the given values:

$s=\frac{0^2-(25^2)}{2\times (-0.5)}$

Simplifying further:

s=−625−1=625s = frac{{ -625}}{{ -1}} = 625s=−<span class="mord m