Question

A car has an initial velocity of 15m/s and an acceleration of 1m/(s^2). How far does the car go in the first 10s after the acceleration begins?

Answer 1

To calculate the distance covered by the car during the first 10 seconds after the acceleration begins, we can use the equation for displacement:

s = ut + (1/2)at^2

Where: s is the displacement (distance covered), u is the initial velocity (15 m/s), a is the acceleration (1 m/s²), and t is the time taken (10 seconds).

Plugging in the given values, we have:

s = (15 m/s)(10 s) + (1/2)(1 m/s²)(10 s)^2 s = 150 m + (1/2)(1 m/s²)(100 s²) s = 150 m + 50 m s = 200 m

Therefore, the car will cover a distance of 200 meters in the first 10 seconds after the acceleration begins.