Question

A block starts from rest and slides down an inclined plane with an acceleration of 2 m/s^2. How far will it go during the first 2 seconds? What will be its velocity at the end of the 2nd second?

Answer 1

To find the distance traveled by the block during the first 2 seconds and its velocity at the end of the 2nd second, we can use the following equations:

1. Distance (s):

   • The distance traveled by an object can be calculated using the equation: s = ut + 0.5at² where u is the initial velocity, t is the time, and a is the acceleration.

2. Velocity (v):

   • The velocity of an object at a given time can be calculated using the equation: v = u + at where u is the initial velocity, t is the time, and a is the acceleration.

Given: Initial velocity (u) = 0 m/s (since the block starts from rest) Acceleration (a) = 2 m/s² Time (t) = 2 s

1. Distance traveled (s): Using the equation s = ut + 0.5at²: s = (0)(2) + 0.5(2)(2²) s = 0 + 0.5(2)(4) s = 0 + 0.5(8) s = 0 + 4 s = 4 meters

   Therefore, the block will go 4 meters during the first 2 seconds.

2. Velocity at the end of the 2nd second (v): Using the equation v = u + at: v = 0 + (2)(2) v = 0 + 4 v = 4 m/s

   Therefore, the velocity of the block at the end of the 2nd second will be 4 m/s.