To find the distance traveled by the body in the first 5 seconds and the next 5 seconds, we need to determine the acceleration of the body first.
Given: Initial velocity (u) = 0 m/s (starting from rest) Final velocity (v) = 20 m/s Time (t) = 2 seconds
The formula to calculate acceleration (a) is:
a = (v - u) / t
Substituting the given values:
a = (20 m/s - 0 m/s) / 2 s a = 20 m/s / 2 s a = 10 m/s²
Since the body is uniformly accelerated, we can use the following kinematic equation to find the distance traveled (s):
s = ut + (1/2)at²
Calculating the distance traveled in the first 5 seconds (t1 = 5 s):
s1 = 0 m/s * 5 s + (1/2) * 10 m/s² * (5 s)² s1 = 0 m + (1/2) * 10 m/s² * 25 s² s1 = 0 m + 125 m s1 = 125 m
Therefore, the distance traveled in the first 5 seconds is 125 meters.
Now, let's calculate the distance traveled in the next 5 seconds (t2 = 5 s):
Since the body has already reached its final velocity of 20 m/s in the first 2 seconds, the velocity remains constant at 20 m/s for the next 5 seconds.
s2 = 20 m/s * 5 s s2 = 100 m
Therefore, the distance traveled in the next 5 seconds is 100 meters.